# Line slope calculator 2x+5y=26

**Straight line given by points A[3; 4] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+5.2

**Canonical form of the line equation:**2x+5y-26 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -2t+4 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 13

**Y intercept:**y

_{0}= q = 5.2

**Distance line from the origin:**d

_{0}= 4.8281

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**5x-2y-21.5 = 0

**Vector OA = (3; 4) ; |OA| = 5**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 32**

**Angle ∠ AOB = 39°5'38″ = 0.6823 rad**